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c^2=2754
We move all terms to the left:
c^2-(2754)=0
a = 1; b = 0; c = -2754;
Δ = b2-4ac
Δ = 02-4·1·(-2754)
Δ = 11016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11016}=\sqrt{324*34}=\sqrt{324}*\sqrt{34}=18\sqrt{34}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{34}}{2*1}=\frac{0-18\sqrt{34}}{2} =-\frac{18\sqrt{34}}{2} =-9\sqrt{34} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{34}}{2*1}=\frac{0+18\sqrt{34}}{2} =\frac{18\sqrt{34}}{2} =9\sqrt{34} $
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